C Exercises: Compute multiplication table of a given integer

C For Loop: Exercise-6 with Solution

Write a program in C to display the multiplication table for a given integer.

Visual Presentation:

Sample Solution:

C Code:

#include <stdio.h>  // Include the standard input/output header file.

int main() {
    int j, n;  // Declare variables 'j' for loop counter and 'n' for user input.

    printf("Input the number (Table to be calculated) : ");  // Print a message to prompt user input.
    scanf("%d", &n);  // Read the value of 'n' from the user.
    printf("\n");  // Print a newline for formatting.

    for (j = 1; j <= 10; j++) {  // Start a for loop to calculate the table up to 10.
        printf("%d X %d = %d \n", n, j, n * j);  // Print the multiplication expression and result.
    }
    return 0;
}

Sample Output:

Input the number (Table to be calculated) : 15                                                                
                                                                                                              
15 X 1 = 15                                                                                                   
15 X 2 = 30                                                                                                   
15 X 3 = 45                                                                                                   
15 X 4 = 60                                                                                                   
15 X 5 = 75                                                                                                   
15 X 6 = 90                                                                                                   
15 X 7 = 105                                                                                                  
15 X 8 = 120                                                                                                  
15 X 9 = 135                                                                                                  
15 X 10 = 150

Explanation:

for (j = 1; j <= 10; j++) {
  printf("%d X %d = %d \n", n, j, n * j);
}

In the above for loop, the variable j is initialized to 1, and the loop will continue as long as j is less than or equal to 10. In each iteration of the loop, the printf function will print a formatted string to the console.

The string will display the value of n, the value of j, and the product of n and j (i.e., nj). The placeholders %d will be replaced by the values of n, j, and nj, respectively. Additionally, the string will include a newline character (\n) to create a new line after each product.

The loop will increment the value of j by 1, and the process will repeat until the condition j<=10 is no longer true.

Flowchart:

C Programming Code Editor:

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