﻿ C exercises: Convert a string to a long integer - w3resource

# C Exercises: Convert a string to a long integer

## C Variable Type : Exercise-3 with Solution

Write a C program to convert a string to a long integer.

Sample Solution:

C Code:

``````#include<stdio.h>
#include<stdlib.h>
int main ()
{
char buffer[] = "2016 40a0b0 -1101110100110111100110 0x5abfff";
char * ptr_end;
long int i1, i2, i3, i4;

i1 = strtol (buffer,&ptr_end,10);
i2 = strtol (ptr_end,&ptr_end,16);
i3 = strtol (ptr_end,&ptr_end,2);
i4 = strtol (ptr_end,NULL,0);
printf ("\nIn decimals: %ld, %ld, %ld, %ld.\n\n", i1, i2, i3, i4);
return 0;
}
```
```

Sample Output:

```In decimals: 2016, 4235440, -3624422, 5947391.
```

C Programming Code Editor:

```#include<stdio.h>
#include<stdlib.h>

int main ()
{
char buffer[] = "2016 40a0b0 -1101110100110111100110 0x5abfff";
char * ptr_end;
long int i1, i2, i3, i4;

i1 = strtol (buffer,&ptr_end,10);
i2 = strtol (ptr_end,&ptr_end,16);
i3 = strtol (ptr_end,&ptr_end,2);
i4 = strtol (ptr_end,NULL,0);

printf ("\nIn decimals: %ld, %ld, %ld, %ld.\n\n", i1, i2, i3, i4);

return 0;
}```

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