﻿ Java exercises: Find the second largest element in an array - w3resource

# Java Array Exercises: Find the second largest element in an array

## Java Array: Exercise-17 with Solution

Write a Java program to find the second largest element in an array.

Sample Solution:

Java Code :

``````import java.util.Arrays;
public class Exercise17 {
public static void main(String[] args) {

int[] my_array = {
1789, 2035, 1899, 1456, 2013,
1458, 2458, 1254, 1472, 2365,
1456, 2165, 1457, 2456};

int max = my_array[0];
int second_max = my_array[0];

System.out.println("Original numeric array : "+Arrays.toString(my_array));

for (int i = 0; i < my_array.length; i++) {

if (my_array[i] > max) {
second_max = max;
max = my_array[i];

} else if (my_array[i] > second_max) {
second_max = my_array[i];

}
}

System.out.println("Second largest number is : " + second_max);

}
}
```
```

Sample Output:

```Original numeric array : [1789, 2035, 1899, 1456, 2013, 1458, 2458, 1254, 1472, 2365, 1456, 2165, 1457, 2456]
Second largest number is : 2456
```

Java Code Editor:

```import java.util.Arrays;
public class Exercise17 {
public static void main(String[] args) {

int[] my_array = {
1789, 2035, 1899, 1456, 2013,
1458, 2458, 1254, 1472, 2365,
1456, 2165, 1457, 2456};

int max = my_array[0];
int second_max = my_array[0];

System.out.println("Original numeric array : "+Arrays.toString(my_array));

for (int i = 0; i < my_array.length; i++) {

if (my_array[i] > max) {
second_max = max;
max = my_array[i];

} else if (my_array[i] > second_max) {
second_max = my_array[i];

}
}

System.out.println("Second largest number is : " + second_max);

}
}```

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