Python: Print structure time from given number of seconds

Python Operating System Services: Exercise-25 with Solution

Write a Python program that takes a given number of seconds and pass since epoch as an argument. Print structure time in local time.

Sample Solution:

Python Code :

import time
result = time.localtime(414538698)
print("\nResult:", result)
print("\nYear:", result.tm_year)

Sample Output:

Result: time.struct_time(tm_year=1983, tm_mon=2, tm_mday=19, tm_hour=21, tm_min=38, tm_sec=18, tm_wday=5, tm_yday=50, tm_isdst=0)

Year: 1983

Python Code Editor:

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Python: Unpack a Tuple

>>> items = (0, 'b', 'one', 10,  11, 'zero')
>>> a, b, c, d, e, f = items
>>> print(f)
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>>> print(b)
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>>> print(a)