# C Exercises: Calculate root of Quadratic Equation

## C Conditional Statement : Exercise-11 with Solution

Write a C program to calculate root of Quadratic Equation.

Test Data :

Input the value of a,b & c : 1 5 7
Expected Output :
Root are imaginary;
No solution.

Sample Solution :-

C Code:

```#include <stdio.h>
#include <math.h>

void main()
{
int a,b,c,d;
float x1,x2;

printf("Input the value of a,b & c : ");
scanf("%d%d%d",&a,&b,&c);
d=b*b-4*a*c;
if(d==0)
{
printf("Both roots are equal.\n");
x1=-b/(2.0*a);
x2=x1;
printf("First  Root Root1= %f\n",x1);
printf("Second Root Root2= %f\n",x2);
}
else if(d>0)
{
printf("Both roots are real and diff-2\n");
x1=(-b+sqrt(d))/(2*a);
x2=(-b-sqrt(d))/(2*a);
printf("First  Root Root1= %f\n",x1);
printf("Second Root root2= %f\n",x2);
}
else
printf("Root are imeainary;\nNo Solution. \n");
}
```

Flowchart :

Code Editor :

```#include <stdio.h>
#include <math.h>

void main()
{
int a,b,c,d;
float x1,x2;

printf("Input the value of a,b & c : ");
scanf("%d%d%d",&a,&b,&c);
d=b*b-4*a*c;
if(d==0)
{
printf("Both roots are equal.\n");
x1=-b/(2.0*a);
x2=x1;
printf("First  Root Root1= %f\n",x1);
printf("Second Root Root2= %f\n",x2);
}
else if(d>0)
{
printf("Both roots are real and diff-2\n");
x1=(-b+sqrt(d))/(2*a);
x2=(-b-sqrt(d))/(2*a);
printf("First  Root Root1= %f\n",x1);
printf("Second Root root2= %f\n",x2);
}
else
printf("Root are imaginary;\nNo Solution. \n");
}```

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