C Exercises: Find the row with maximum number of 1s

C Array: Exercise-60 with Solution

Write a program in C to find the row with the maximum number of 1s.

Sample Solution:

C Code:

#include <stdio.h>
#define R 5
#define C 5
 

int getFirstOccur(int arr1[], int l, int h)
{
if(h >= l)
{
    int mid = l + (h - l)/2; 
    if ( ( mid == 0 || arr1[mid-1] == 0) && arr1[mid] == 1)
    return mid;
    else if (arr1[mid] == 0)
    return getFirstOccur(arr1, (mid + 1), h);
    else
    return getFirstOccur(arr1, l, (mid -1));
}
return -1;
}
int findRowMaxOne(int arr2d[R][C])
{
    int max_row_index = 0, max = -1; 
    int i, index;
    for (i = 0; i < R; i++)
    {
    index = getFirstOccur (arr2d[i], 0, C-1);
    if (index != -1 && C-index > max)
    {
        max = C - index;
        max_row_index = i;
    }
    }
    return max_row_index;
}
 
int main()
{
    int arr2d[R][C] = { {0, 1, 0, 1,1},
                       {1, 1, 1, 1, 1},
                       {1, 0, 0, 1, 0},
                       {0, 0, 0, 0, 0},
                       {1, 0, 0, 0, 1}
    };
    int i,j;					   
    //------------- print original 2D array ------------------	
	printf("The given 2D array is :  \n");
	for(i = 0; i < R; i++)
	{
	for(j=0; j<C ; j++)
	{
	printf("%d  ", arr2d[i][j]);
	}

	printf("\n");
    } 
//------------------------------------------------------ 					   
    printf("The index of row with maximum 1s is:  %d " , findRowMaxOne(arr2d));
    return 0;
}

Sample Output:

The given 2D array is :  
0  1  0  1  1  
1  1  1  1  1  
1  0  0  1  0  
0  0  0  0  0  
1  0  0  0  1  
The index of row with maximum 1s is:  1

Flowchart:

C Programming Code Editor:

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