C++ Exercises: Check a given array of integers and return true if the given array contains either 2 even or 2 odd values all next to each other

C++ Basic Algorithm: Exercise-111 with Solution

Check for Two Adjacent Even or Odd Numbers in Array

Write a C++ program to check a given array of integers. The program will return true if the given array contains either 2 even or 2 odd values all next to each other.

Sample Solution:

C++ Code :

#include <iostream>  // Including input-output stream header file

using namespace std;  // Using standard namespace

// Function definition that checks if there are two consecutive even or odd numbers in the array
static bool test(int numbers[], int arr_length)
{
    int tot_odd = 0, tot_even = 0;  // Initializing counters for odd and even numbers

    // Loop through the array to find consecutive even or odd numbers
    for (int i = 0; i < arr_length; i++)
    {
        // Check conditions for consecutive even or odd numbers
        if (tot_odd < 2 && tot_even < 2)
        {
            if (numbers[i] % 2 == 0)
            {
                tot_even++;  // Increment count for even numbers
                tot_odd = 0; // Reset count for odd numbers
            }
            else
            {
                tot_odd++;   // Increment count for odd numbers
                tot_even = 0; // Reset count for even numbers
            }
        }
    }

    // Return true if there are two consecutive odd or even numbers, otherwise false
    return tot_odd == 2 || tot_even == 2;
}

int main() 
{  
    // Different test cases with arrays of integers
    int nums1[] = {3, 5, 1, 3, 7};   // No two consecutive even or odd numbers
    int arr_length = sizeof(nums1) / sizeof(nums1[0]);
    cout << test(nums1, arr_length) << endl; 

    int nums2[] = {1, 2, 3, 4};  // No two consecutive even or odd numbers
    arr_length = sizeof(nums2) / sizeof(nums2[0]);
    cout << test(nums2, arr_length) << endl;

    int nums3[] = {3, 3, 5, 5, 5, 5};  // Two consecutive odd numbers
    arr_length = sizeof(nums3) / sizeof(nums3[0]);
    cout << test(nums3, arr_length) << endl;

    int nums4[] = {2, 4, 5, 6};  // Two consecutive even numbers
    arr_length = sizeof(nums4) / sizeof(nums4[0]);
    cout << test(nums4, arr_length) << endl;

    return 0;  // Returning 0 to indicate successful completion of the program
}

Sample Output:

1
0
1
1

Visual Presentation:

Flowchart:

C++ Code Editor:

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