Java Exercises: Test if a given number is a perfect square or not
Java Basic: Exercise-197 with Solution
Write a Java program to test if a given number (positive integer ) is a perfect square or not.
Input number: 3 Output: 1 2 3 8 9 4 7 6 5Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.*;
public class Solution {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Input a positive integer: ");
int n = in .nextInt();
System.out.print("Is the said number perfect square? " + is_Perfect_Square(n));
}
public static boolean is_Perfect_Square(int n) {
int x = n % 10;
if (x == 2 || x == 3 || x == 7 || x == 8) {
return false;
}
for (int i = 0; i <= n / 2 + 1; i++) {
if ((long) i * i == n) {
return true;
}
}
return false;
}
}
Sample Output:
Input a positive integer: 6 Is the said number perfect square? false
Flowchart:

Java Code Editor:
Company: LinkedIn
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Previous: Write a Java program to create a spiral array of n * n sizes from a given integer n.
Next: Write a Java program to get the position of a given prime number.
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Java: Tips of the Day
How to remove leading zeros from alphanumeric text?
Regex is the best tool for the job; what it should be depends on the problem specification. The following removes leading zeroes, but leaves one if necessary (i.e. it wouldn't just turn "0" to a blank string).
s.replaceFirst("^0+(?!$)", "")
The ^ anchor will make sure that the 0+ being matched is at the beginning of the input. The (?!$) negative lookahead ensures that not the entire string will be matched.
Test harness:
String[] in = { "01234", // "[1234]" "0001234a", // "[1234a]" "101234", // "[101234]" "000002829839", // "[2829839]" "0", // "[0]" "0000000", // "[0]" "0000009", // "[9]" "000000z", // "[z]" "000000.z", // "[.z]" }; for (String s : in) { System.out.println("[" + s.replaceFirst("^0+(?!$)", "") + "]"); }
Ref: https://bit.ly/2Qdcl8a
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