Java Programming Exercies

Java Exercises: Bucket Sort Algorithm

Java Sorting Algorithm: Exercise-19 with Solution

Write a Java program to sort an array of given integers using Bucket Sort Algorithm.

Bucket sort is a sorting algorithm that works by distributing the elements of an array into a number of buckets. Each bucket is then sorted individually, either using a different sorting algorithm, or by recursively applying the bucket sorting algorithm. It is a distribution sort, a generalization of pigeonhole sort, and is a cousin of radix sort in the most-to-least significant digit flavor.

Sample Solution:

Java Code:

import java.util.Arrays;
public class BucketSort 
    static int[] sort(int[] nums, int max_value) 
        // Bucket Sort
        int[] Bucket = new int[max_value + 1];
        int[] sorted_nums = new int[nums.length];
         for (int i = 0; i < nums.length; i++)
          int outPos = 0;
         for (int i = 0; i < Bucket.length; i++)
              for (int j = 0; j < Bucket[i]; j++)
                  sorted_nums[outPos++] = i;
          return sorted_nums;
    static int max_value(int[] nums) 
        int max_value = 0;
        for (int i = 0; i < nums.length; i++)
            if (nums[i] > max_value)
                max_value = nums[i];
        return max_value;
// Method to test above
    public static void main(String args[])
        int nums[] = {7, 3, 2, 1, 0, 45};
       int max_value = max_value(nums);
        System.out.println("Original Array:");
        nums = sort(nums, max_value);
        System.out.println("Sorted Array:");

Sample Output:

Original Array:
[7, 3, 2, 1, 0, 45]
Sorted Array:
[0, 1, 2, 3, 7, 45]


Sort an array of given integers using Bucket Sort Algorithm

Java Code Editor:

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