Python Exercises: Iterated Cube Root

Python Basic - 1: Exercise-150 with Solution

Write a Python program that takes a positive integer and calculates the cube root of the number until the number is less than three. Count the number of steps to complete the task.

Sample Data:

(3) -> 1
(39) -> 2
(10000) -> 2

Sample Solution-1:

Python Code:

def test(n):
	ctr = 0
	while n >= 3:
	  n =  n ** (1./3.)
	  ctr = ctr + 1
	return 'Not a positive number!' if n < 0 else ctr

n= int(input("Input a positive integer:"))
print(test(n))

Sample Output:

Input a positive integer: 3
1
Input a positive integer: 39
2
Input a positive integer: 10000
2
Input a positive integer: -4
Not a positive number!

Flowchart:

Sample Solution-2:

Python Code:

def test(n):
  return "Not a positive number!" if n < 0 else 0 if n<3 else test(int(n**(1./3.)))+1
n= int(input("Input a positive integer:"))
print(test(n))

Sample Output:

Input a positive integer: 14
1
Input a positive integer: -5
Not a positive number!

Flowchart:

Python Code Editor:

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