Python: Most frequent element in a given list of numbers
Python List: Exercise - 261 with Solution
Write a Python program to get the most frequent element in a given list of numbers.
- Use set() to get the unique values in nums.
- Use max() to find the element that has the most appearances.
Sample Solution:
Python Code:
def most_frequent(nums):
return max(set(nums), key = nums.count)
print(most_frequent([1, 2, 1, 2, 3, 2, 1, 4, 2]))
nums = [2,3,8,4,7,9,8,2,6,5,1,6,1,2,3,2,4,6,9,1,2]
print ("Original list:")
print(nums)
print("Item with maximum frequency of the said list:")
print(most_frequent(nums))
nums = [1, 2, 3, 1, 2, 3, 2, 1, 4, 3, 3]
print ("\nOriginal list:")
print(nums)
print("Item with maximum frequency of the said list:")
print(most_frequent(nums))
Sample Output:
2 Original list: [2, 3, 8, 4, 7, 9, 8, 2, 6, 5, 1, 6, 1, 2, 3, 2, 4, 6, 9, 1, 2] Item with maximum frequency of the said list: 2 Original list: [1, 2, 3, 1, 2, 3, 2, 1, 4, 3, 3] Item with maximum frequency of the said list: 3
Flowchart:

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Previous: Write a Python program to check if a given function returns True for at least one element in the list.
Next: Write a Python program to move the specified number of elements to the end of the given list.
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Python: Tips of the Day
Returns True if the provided function returns True for every element in the list, False otherwise:
Example:
def tips_every(lst, fn=lambda x: x): return all(map(fn, lst)) print(tips_every([2, 4, 3], lambda x: x > 1)) print(tips_every([1, 2, 3]))
Output:
True True
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