Rust Program: Filter Odd numbers

Rust Iterators and Iterator Adapters: Exercise-9 with Solution

Write a Rust program that iterates over a range of numbers and filters out odd numbers.

Sample Solution:

Rust Code:

fn main() {
    // Define the range of numbers from 1 to 10 (inclusive)
    let range = 1..=20;

    // Filter out even numbers using iterator adapters
    let odd_numbers: Vec<i32> = range.filter(|&x| x % 2 != 0).collect();

    // Print the filtered odd numbers
    println!("Filtered odd numbers: {:?}", odd_numbers);
}

Output:

Filtered odd numbers: [1, 3, 5, 7, 9, 11, 13, 15, 17, 19]

Explanation:

In the exercise above,

• let range = 1..=10;: This line defines a range from 1 to 10 (inclusive) using the ..= syntax, which includes both the start and end values.
• let odd_numbers: Vec<i32> = range.filter(|&x| x % 2 != 0).collect();: It filters the numbers in the range using the "filter" iterator adapter. The closure |&x| x % 2 != 0 is applied to each element of the range, returning 'true' for odd numbers (those with a remainder when divided by 2). The "collect()" method collects the filtered odd numbers into a vector.
• println!("Filtered odd numbers: {:?}", odd_numbers);: Finally, it prints the vector containing the filtered odd numbers.

Rust Code Editor:

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