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C Exercises: Sum of all elements in an array

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C Pointer : Exercise-16 with Solution

Write a program in C to compute the sum of all elements in an array using pointers.
Test Data :
Input the number of elements to store in the array (max 10) : 5
Input 5 number of elements in the array :
element - 1 : 2
element - 2 : 3
element - 3 : 4
element - 4 : 5
element - 5 : 6
Expected Output :

 The sum of array is : 20 

C Code:

#include <stdio.h>
void main() 
{
   int arr1[10];
   int i,n, sum = 0;
   int *pt;
   
 	printf("\n\n Pointer : Sum of all elements in an array :\n"); 
	printf("------------------------------------------------\n"); 
	
   printf(" Input the number of elements to store in the array (max 10) : ");
   scanf("%d",&n);
   
   printf(" Input %d number of elements in the array : \n",n);
   for(i=0;i<n;i++)
      {
	  printf(" element - %d : ",i+1);
	  scanf("%d",&arr1[i]);
	  } 	

   pt = arr1; // pt store the base address of array arr1
 
   for (i = 0; i < n; i++) {
      sum = sum + *pt;
      pt++;
   }
 
   printf(" The sum of array is : %d\n\n", sum);
}

Flowchart :

Flowchart: Sum of all elements in an array

C Practice online:


#include <stdio.h>
void main() 
{
   int arr1[10];
   int i,n, sum = 0;
   int *pt;
   
 	printf("\n\n Pointer : Sum of all elements in an array :\n"); 
	printf("------------------------------------------------\n"); 
	
   printf(" Input the number of elements to store in the array (max 10) : ");
   scanf("%d",&n);
   
   printf(" Input %d number of elements in the array : \n",n);
   for(i=0;i<n;i++)
      {
	  printf(" element - %d : ",i+1);
	  scanf("%d",&arr1[i]);
	  } 	

   pt = arr1; // pt store the base address of array arr1
 
   for (i = 0; i < n; i++) {
      sum = sum + *pt;
      pt++;
   }
 
   printf(" The sum of array is : %d\n\n", sum);
}

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