C Exercises: Sum of all even values between two input integers, exclusive input values

C Basic Declarations and Expressions: Exercise-114 with Solution

Write a C program that accepts two integer values and calculates the sum of all even values between them.

Sample Solution:

C Code:

#include <stdio.h>

int main () {
    int y, i, z;
    int l, m, n, ctr1 = 0, ctr2 = 0;

    // Prompt user for input
    printf("Input two numbers (integer values):\n");

    // Read two integer values from user and store them in 'm' and 'n'
    scanf("%d %d", &m, &n);

    ctr1 = 0; // Reset counter 1
    printf("\nSum of all even values between %d and %d\n", m, n);

    // Check if 'm' is greater than 'n'
    if (m > n) {
        // Loop to find and sum all even numbers between 'n' and 'm'
        for (l = n + 1; l < m; l++){
            if (l % 2 == 0){
                ctr1 += l; // Accumulate even numbers in counter 1
            }
        }
        printf("%d\n", ctr1); // Print the sum of even numbers
    }
    else {
        // Loop to find and sum all even numbers between 'm' and 'n'
        for (l = m + 1; l < n; l++){
            if (l % 2 == 0){
                ctr2 += l; // Accumulate even numbers in counter 2
            }
        }
        printf("%d\n", ctr2); // Print the sum of even numbers
    }

    return 0; // End of program
}

Sample Output:

Input two numbers (integer values):
25
45

Sum of all even values between 25 and 45
350

Sample Output:

Input two numbers (integer values):
27
13

Sum of all even values between 27 and 13
140

Flowchart:

C programming Code Editor:

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