﻿ C Program: Display n natural numbers and their sum - w3resource

C Exercises: Display n natural numbers and their sum

C For Loop: Exercise-3 with Solution

Write a program in C to display n terms of natural number and their sum.

Pictorial Presentation:

Sample Solution:

C Code:

``````#include <stdio.h>
void main()
{
int i,n,sum=0;
printf("Input Value of terms : ");
scanf("%d",&n);
printf("\nThe first %d natural numbers are:\n",n);
for(i=1;i<=n;i++)
{
printf("%d ",i);
sum+=i;
}
printf("\nThe Sum of natural numbers upto %d terms : %d \n",n,sum);

}
```
```

Sample Output:

```Input Value of terms : 7

The first 7 natural number is :
1 2 3 4 5 6 7
The Sum of Natural Number upto 7 terms : 28
```

Flowchart:

C Programming Code Editor:

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C Programming: Tips of the Day

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

```char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
```
Here's a solution:
```char ch = 0xC0;
printf("%x", ch & 0xff);
```

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM