C Exercises: Display the sum of n number of odd natural number

C For Loop: Exercise-8 with Solution

Write a C program to display the n terms of odd natural numbers and their sum.
like: 1 3 5 7 ... n

Pictorial Presentation:

Sample Solution:

C Code:

#include <stdio.h>
void main()
{
   int i,n,sum=0;

   printf("Input number of terms : ");
   scanf("%d",&n);
   printf("\nThe odd numbers are :");
   for(i=1;i<=n;i++)
   {
     printf("%d ",2*i-1);
     sum+=2*i-1;
   }
   printf("\nThe Sum of odd Natural Number upto %d terms : %d \n",n,sum);
}

Sample Output:

Input number of terms : 10                                                                                    
                                                                                                              
The odd numbers are :1 3 5 7 9 11 13 15 17 19                                                                 
The Sum of odd Natural Number upto 10 terms : 100 

Explanation:

for (i = 1; i <= n; i++) {
  printf("%d ", 2 * i - 1);
  sum += 2 * i - 1;
}

In the said loop, the variable i is initialized to 1, and the loop will continue as long as i is less than or equal to the value of variable 'n'. In each iteration of the loop, the printf function will print the value of (2*i-1) to the console, followed by a space character.

Additionally, the value of (2*i-1) will be added to the variable 'sum' in each iteration of the loop.

The loop will increment the value of i by 1, and the process will repeat until the condition i<=n is no longer true.

Flowchart:

C Programming Code Editor:

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