﻿ C Program: Display the sum of n number of odd natural number - w3resource

# C Exercises: Display the sum of n number of odd natural number

## C For Loop: Exercise-8 with Solution

Write a program in C to display the n terms of odd natural number and their sum like:
1 3 5 7 ... n

Pictorial Presentation:

Sample Solution:

C Code:

``````#include <stdio.h>
void main()
{
int i,n,sum=0;

printf("Input number of terms : ");
scanf("%d",&n);
printf("\nThe odd numbers are :");
for(i=1;i<=n;i++)
{
printf("%d ",2*i-1);
sum+=2*i-1;
}
printf("\nThe Sum of odd Natural Number upto %d terms : %d \n",n,sum);
}
```
```

Sample Output:

```Input number of terms : 10

The odd numbers are :1 3 5 7 9 11 13 15 17 19
The Sum of odd Natural Number upto 10 terms : 100
```

Flowchart:

C Programming Code Editor:

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## C Programming: Tips of the Day

You are seeing the ffffff because char is signed on your system. In C, vararg functions such as printf will promote all integers smaller than int to int. Since char is an integer (8-bit signed integer in your case), your chars are being promoted to int via sign-extension.

Since c0 and 80 have a leading 1-bit (and are negative as an 8-bit integer), they are being sign-extended while the others in your sample don't.

```char    int
c0 -> ffffffc0
80 -> ffffff80
61 -> 00000061
```
Here's a solution:
```char ch = 0xC0;
printf("%x", ch & 0xff);
```

This will mask out the upper bits and keep only the lower 8 bits that you want.

Ref : https://bit.ly/3vOLizM