# C Programming: Count the digits in a number that divide it

## C Programming Mathematics: Exercise-33 with Solution

Write a C program to count the digits in a given number that divide it.

Example:

Input (integer value) = 9

Digit of the said number is 9

9 divides 9

So, Output = 1

Input (integer value) = 27

Digits of the said number are 2, 7

2 cannot divides 27

7 cannot divides 27

So, Output = 0

Input (integer value) = 2245

Digits of the said number are 2, 2, 4, 5

2 cannot divides 2245

2 cannot divides 2245

4 cannot divides 2245

5 divides 2245

So, Output = 0

**Test Data:**

(9) -> 1

(27) -> 0

(145) -> 2

(2245) -> 1

(2222) -> 4

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
int test(int n){
int temp = n;
int result = 0;
while(temp!=0){
int d = temp % 10;
temp/=10;
if(n % d == 0)
result++;
}
return result;
}
int main(void) {
int n = 9;
printf("n = %d",n);
printf("\nNumber of digits in the said number that divide it = %d", test(n));
n = 27;
printf("\nn = %d",n);
printf("\nNumber of digits in the said number that divide it = %d", test(n));
n = 145;
printf("\nn = %d",n);
printf("\nNumber of digits in the said number that divide it = %d", test(n));
n = 2245;
printf("\nn = %d",n);
printf("\nNumber of digits in the said number that divide it = %d", test(n));
n = 2222;
printf("\nn = %d",n);
printf("\nNumber of digits in the said number that divide it = %d", test(n));
}
```

Sample Output:

n = 9 Number of digits in the said number that divide it = 1 n = 27 Number of digits in the said number that divide it = 0 n = 145 Number of digits in the said number that divide it = 2 n = 2245 Number of digits in the said number that divide it = 1 n = 2222 Number of digits in the said number that divide it = 4

**Flowchart: **

**C Programming Code Editor:**

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