# C Programming: Number sums and their reverses

## C Programming Mathematics: Exercise-32 with Solution

Write a C programming to check whether a given integer can be expressed as the sum of any non-negative integer and its reverse. Return true otherwise false.

Example:

Input: = 554

Output: true

Explanation: 371 + 173 = 554

Input: = 51

Output: false

Explanation: It cannot be expressed as per said condition.

Input: = 55

Output: true

Explanation: 41 + 14 = 55

Input: = 181

Output: true

Explanation: 140 + 041 = 181

**Test Data:**

(554) -> 1

(51) -> 0

(55) -> 1

(181) -> 1

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int rev(int n){
int result = 0, t, r;
for(t=n;n!=0;n=n/10){
r=n % 10;
result=result*10+r;
}
return result;
}
bool test(int n){
if(n==0) return true;
for(int i=n/2;i<n;i++){
if(i+rev(i)==n){
return true;
}
}
return false;
}
int main(void) {
int n = 544;
printf("n = %d",n);
printf("\nTest said number can be expressed as the sum of any non-negative integer and its reverse = %d", test(n));
n = 51;
printf("\nn = %d",n);
printf("\nTest said number can be expressed as the sum of any non-negative integer and its reverse = %d", test(n));
n = 55;
printf("\nn = %d",n);
printf("\nTest said number can be expressed as the sum of any non-negative integer and its reverse = %d", test(n));
n = 181;
printf("\nn = %d",n);
printf("\nTest said number can be expressed as the sum of any non-negative integer and its reverse = %d", test(n));
}
```

Sample Output:

n = 544 Test said number can be expressed as the sum of any non-negative integer and its reverse = 1 n = 51 Test said number can be expressed as the sum of any non-negative integer and its reverse = 0 n = 55 Test said number can be expressed as the sum of any non-negative integer and its reverse = 1 n = 181 Test said number can be expressed as the sum of any non-negative integer and its reverse = 1

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