C Programming: Largest number, swapping two digits in a number
C Programming Mathematics: Exercise-31 with Solution
Write a C programming to calculate the largest number that can be generated by swapping just two digits at most once
Test Data:
(89) -> 98 [Swapping 8 and 9]
(568) -> 865 [Swapping 8 and 5]
(4499) -> 9494 [Swapping 9 and 4]
(12345) -> 52341 [Swapping 1 and 5]
(7743) -> 52341 [No Swap]
Sample Solution:
C Code:
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
void swap(char *x, char *y) {
char temp = *y;
*y = *x;
*x = temp;
}
int strlen(char *str)
{
int l =0;
while(str[l]!='\0')
{
l++;
}
return l;
}
int test(int num){
char str_num[1000];
char len;
int result;
sprintf(str_num, "%d", num);
len = strlen(str_num);
result = num;
for (int i = 0; i < len; i++) {
for (int j = i+1; j < len; j++) {
swap(str_num+i, str_num+j);
if (atoi(str_num) > result) {
result = atoi(str_num);
}
swap(str_num+i, str_num+j);
}
}
return result;
}
int main(void) {
int n = 89;
printf("n = %d",n);
printf("\nLargest number from the said number swapping two digits = %d", test(n));
n = 568;
printf("\n\nn = %d",n);
printf("\nLargest number from the said number swapping two digits = %d", test(n));
n = 4499;
printf("\n\nn = %d",n);
printf("\nLargest number from the said number swapping two digits = %d", test(n));
n = 12345;
printf("\n\nn = %d",n);
printf("\nLargest number from the said number swapping two digits = %d", test(n));
n = 7743;
printf("\n\nn = %d",n);
printf("\nLargest number from the said number swapping two digits = %d", test(n));
}
Sample Output:
n = 89 Largest number from the said number swapping two digits = 98 n = 568 Largest number from the said number swapping two digits = 865 n = 4499 Largest number from the said number swapping two digits = 9494 n = 12345 Largest number from the said number swapping two digits = 52341 n = 7743 Largest number from the said number swapping two digits = 7743
Flowchart:

C Programming Code Editor:
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Next: Number sums and their reverses.
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C Programming: Tips of the Day
What's the point of const pointers?
const is a tool which you should use in pursuit of a very important C++ concept:
Find bugs at compile-time, rather than run-time, by getting the compiler to enforce what you mean.
Even though it does not change the functionality, adding const generates a compiler error when you're doing things you didn't mean to do. Imagine the following typo:
void foo(int* ptr) { ptr = 0;// oops, I meant *ptr = 0 }
If you use int* const, this would generate a compiler error because you're changing the value to ptr. Adding restrictions via syntax is a good thing in general. Just don't take it too far -- the example you gave is a case where most people don't bother using const.
Ref : https://bit.ly/33Cdn3Q
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