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Java Array Exercises: Print all sub-arrays with 0 sum present in a given array of integers

Java Array: Exercise-55 with Solution

Write a Java program to print all sub-arrays with 0 sum present in a given array of integers.

Example:
Input :
nums1 = { 1, 3, -7, 3, 2, 3, 1, -3, -2, -2 }
nums2 = { 1, 2, -3, 4, 5, 6 }
nums3= { 1, 2, -2, 3, 4, 5, 6 }
Output:
Sub-arrays with 0 sum : [1, 3, -7, 3]
Sub-arrays with 0 sum : [3, -7, 3, 2, 3, 1, -3, -2]
Sub-arrays with 0 sum : [1, 2, -3]
Sub-arrays with 0 sum : [2, -2]

Sample Solution:

Java Code:

import java.util.*;
import java.lang.*;
class solution
{
	public static void print_all_Subarrays(int[] A)
	{
		
		List<Integer> llist = new ArrayList<Integer>();
		for (int i = 0; i < A.length; i++)
		{
			int sum = 0;
			llist.removeAll(llist);
			for (int j = i; j < A.length; j++)
			{
				sum += A[j];
				llist.add(A[j]); 
				if (sum == 0) {
					System.out.println("Sub-arrays with 0 sum : " + llist.toString()); 
				
				}
			}
		}
	}

	public static void main (String[] args)
	{
		int[] nums1 = { 1, 3, -7, 3, 2, 3, 1, -3, -2, -2 };
		System.out.println("\nOriginal array: "+Arrays.toString(nums1));
		print_all_Subarrays(nums1);
		
	              int[] nums2 = { 1, 2, -3, 4, 5, 6 };
		System.out.println("\nOriginal array: "+Arrays.toString(nums2));
		print_all_Subarrays(nums2);
		
		int[] nums3= { 1, 2, -2, 3, 4, 5, 6 };
		System.out.println("\nOriginal array: "+Arrays.toString(nums3));
		print_all_Subarrays(nums3);
	}
}

Sample Output:

                                                                              
Original array: [1, 3, -7, 3, 2, 3, 1, -3, -2, -2]
Sub-arrays with 0 sum : [1, 3, -7, 3]
Sub-arrays with 0 sum : [3, -7, 3, 2, 3, 1, -3, -2]

Original array: [1, 2, -3, 4, 5, 6]
Sub-arrays with 0 sum : [1, 2, -3]

Original array: [1, 2, -2, 3, 4, 5, 6]
Sub-arrays with 0 sum : [2, -2]

Flowchart:

Flowchart: Print all sub-arrays with 0 sum present in a given array of integers

Java Code Editor:

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Java: Tips of the Day

Different between parseInt() and valueOf() in java?

Well, the API for Integer.valueOf(String) does indeed say that the String is interpreted exactly as if it were given to Integer.parseInt(String). However, valueOf(String) returns a new Integer() object whereas parseInt(String) returns a primitive int.

If you want to enjoy the potential caching benefits of Integer.valueOf(int), you could also use this eyesore:

Integer k = Integer.valueOf(Integer.parseInt("123"))

Now, if what you want is the object and not the primitive, then using valueOf(String) may be more attractive than making a new object out of parseInt(String) because the former is consistently present across Integer, Long, Double, etc.

Ref: https://bit.ly/3vRuIPY