# Java: Find the numbers greater than the average of the numbers of a specified array

## Java Basic: Exercise-162 with Solution

Write a Java program that finds numbers greater than the average of an array.

**Visual Presentation:**

**Sample Solution:**

**Java Code:**

```
import java.util.*;
public class Main {
public static void main(String[] args) {
// Initializing an array of integers
Integer nums[] = new Integer[]{1, 4, 17, 7, 25, 3, 100};
double sum = 0; // Initializing the sum variable
// Displaying the original array
System.out.println("Original Array: ");
System.out.println(Arrays.toString(nums));
// Calculating the sum of elements in the array
for(int i = 0; i < nums.length; i++) {
sum = sum + nums[i];
}
// Calculating the average of the elements in the array
double average = (double) sum / nums.length;
// Displaying the average of the array
System.out.println("The average of the said array is: " + average);
System.out.println("The numbers in the said array that are greater than the average are: ");
// Printing numbers greater than the average in the array
for(int i = 0; i < nums.length; i++) {
if(nums[i] > average) {
System.out.println(nums[i]);
}
}
}
}
```

Sample Output:

Original Array: [1, 4, 17, 7, 25, 3, 100] The average of the said array is: 22.428571428571427 The numbers in the said array that are greater than the average are: 25 100

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