﻿ Java - Find the numbers greater than the average of an array

# Java: Find the numbers greater than the average of the numbers of a specified array

## Java Basic: Exercise-162 with Solution

Write a Java program that finds numbers greater than the average of an array.

Pictorial Presentation: Sample Solution:

Java Code:

``````import java.util.*;
public class Solution {
public static void main(String[] args)
{
Integer nums[] = new Integer[]{1, 4, 17, 7, 25, 3, 100};
int sum = 0;
System.out.println("Original Array: ");
System.out.println(Arrays.toString(nums));
for(int i = 0; i < nums.length; i++) {
sum = sum + nums[i];
}
double average = sum / nums.length;
System.out.println("The average of the said array is: " + average);
System.out.println("The numbers in the said array that are greater than the average are: ");
for(int i = 0; i < nums.length; i++) {
if(nums[i] > average) {
System.out.println(nums[i]);
}
}
}
}
```
```

Sample Output:

```Original Array:
[1, 4, 17, 7, 25, 3, 100]
The average of the said array is: 22.0
The numbers in the said array that are greater than the average are:
25
100
```

Flowchart: Java Code Editor: