Java: Find the numbers greater than the average of the numbers of a specified array

Java Basic: Exercise-162 with Solution

Write a Java program that finds numbers greater than the average of an array.

Visual Presentation:

Sample Solution:

Java Code:

import java.util.*;

public class Solution {
    public static void main(String[] args) {
        // Initializing an array of integers
        Integer nums[] = new Integer[]{1, 4, 17, 7, 25, 3, 100};
        
        int sum = 0; // Initializing the sum variable
        
        // Displaying the original array
        System.out.println("Original Array: ");
        System.out.println(Arrays.toString(nums));
        
        // Calculating the sum of elements in the array
        for(int i = 0; i < nums.length; i++) {
            sum = sum + nums[i];
        }
        
        // Calculating the average of the elements in the array
        double average = sum / nums.length;
        
        // Displaying the average of the array
        System.out.println("The average of the said array is: " + average);
        System.out.println("The numbers in the said array that are greater than the average are: ");
        
        // Printing numbers greater than the average in the array
        for(int i = 0; i < nums.length; i++) {
            if(nums[i] > average) {
                System.out.println(nums[i]);
            }
        }
    }
} 

Sample Output:

Original Array: 
[1, 4, 17, 7, 25, 3, 100]
The average of the said array is: 22.0
The numbers in the said array that are greater than the average are:
25
100

Flowchart:

Java Code Editor:

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