﻿ Java: Convert an integer into binary representation

# Java Exercises: Accept an integer and convert it into a binary representation

## Java Basic: Exercise-163 with Solution

Write a Java program that will accept an integer and convert it into a binary representation. Now count the number of bits which is equal to zero of the said binary representation.

Pictorial Presentation: Sample Solution:

Java Code:

``````import java.util.Scanner;
public class Solution {
public static int countBitsTozeroBasedOnString(int n) {
int ctr = 0;
String binaryNumber = Integer.toBinaryString(n);
System.out.print("Binary representation of "+n+" is: "+binaryNumber);
for (char ch : binaryNumber.toCharArray()) {
ctr += ch == '0' ? 1 : 0;
}
return ctr;
}

public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Input first number: ");
int n = in.nextInt();
System.out.println("\nNumber of zero bits: " + countBitsTozeroBasedOnString(n));
}
}
```
```

Sample Output:

```Input first number:  25
Binary representation of 25 is: 11001
Number of zero bits: 2s
```

Flowchart: Java Code Editor:

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## Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

```public static List<String> anagrams(String input) {
if (input.length() <= 2) {
return input.length() == 2
? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
: Collections.singletonList(input);
}
return IntStream.range(0, input.length())
.mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
.flatMap(entry ->
anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
.stream()
.map(s -> entry.getValue() + s))
.collect(Collectors.toList());
}
```