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Java Exercises: Accept an integer and convert it into a binary representation

Java Basic: Exercise-163 with Solution

Write a Java program that will accept an integer and convert it into a binary representation. Now count the number of bits which is equal to zero of the said binary representation.

Pictorial Presentation:

Java Basic Exercises: Accept an interger and convert it into a binary representation.

Sample Solution:

Java Code:

import java.util.Scanner;
public class Solution {	
	public static int countBitsTozeroBasedOnString(int n) {
    int ctr = 0;
    String binaryNumber = Integer.toBinaryString(n);
	System.out.print("Binary representation of "+n+" is: "+binaryNumber);
    for (char ch : binaryNumber.toCharArray()) {
      ctr += ch == '0' ? 1 : 0;
    }
    return ctr;
  }	
	
    public static void main(String[] args) {
		Scanner in = new Scanner(System.in);
        System.out.print("Input first number: ");
        int n = in.nextInt();
		System.out.println("\nNumber of zero bits: " + countBitsTozeroBasedOnString(n));
		}
}

Sample Output: 

Input first number:  25
Binary representation of 25 is: 11001
Number of zero bits: 2s

Flowchart:

Flowchart: Java exercises: Accept an interger and convert it into a binary representation.

Java Code Editor:

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Previous: Write a Java program to find the numbers greater than the average of the numbers of a given array.
Next: Write a Java program to divide the two given integers using subtraction operator.

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Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

public static List<String> anagrams(String input) {
    if (input.length() <= 2) {
        return input.length() == 2
                ? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
                : Collections.singletonList(input);
    }
    return IntStream.range(0, input.length())
            .mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
            .flatMap(entry ->
                    anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
                            .stream()
                            .map(s -> entry.getValue() + s))
            .collect(Collectors.toList());
}

Ref: https://bit.ly/3rvAdAK