Java Exercises: Accept an integer and convert it into a binary representation
Java Basic: Exercise-163 with Solution
Write a Java program that will accept an integer and convert it into a binary representation. Now count the number of bits which is equal to zero of the said binary representation.
Pictorial Presentation:

Sample Solution:
Java Code:
import java.util.Scanner;
public class Solution {
public static int countBitsTozeroBasedOnString(int n) {
int ctr = 0;
String binaryNumber = Integer.toBinaryString(n);
System.out.print("Binary representation of "+n+" is: "+binaryNumber);
for (char ch : binaryNumber.toCharArray()) {
ctr += ch == '0' ? 1 : 0;
}
return ctr;
}
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Input first number: ");
int n = in.nextInt();
System.out.println("\nNumber of zero bits: " + countBitsTozeroBasedOnString(n));
}
}
Sample Output:
Input first number: 25 Binary representation of 25 is: 11001 Number of zero bits: 2s
Flowchart:

Java Code Editor:
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Previous: Write a Java program to find the numbers greater than the average of the numbers of a given array.
Next: Write a Java program to divide the two given integers using subtraction operator.
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Java: Tips of the Day
Java: Anagrams
Generates all anagrams of a string.
public static List<String> anagrams(String input) { if (input.length() <= 2) { return input.length() == 2 ? Arrays.asList(input, input.substring(1) + input.substring(0, 1)) : Collections.singletonList(input); } return IntStream.range(0, input.length()) .mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1))) .flatMap(entry -> anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1)) .stream() .map(s -> entry.getValue() + s)) .collect(Collectors.toList()); }
Ref: https://bit.ly/3rvAdAK
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