﻿ Java: Split an array into even number first and odd second

# Java Exercises: Partition an given array of integers into even number first and odd number second

## Java Basic: Exercise-176 with Solution

Write a Java program to partition an given array of integers into even number first and odd number second.

Original array: [7, 2, 4, 1, 3, 5, 6, 8, 2, 10]
After partition the said array becomes: [10, 2, 4, 2, 8, 6, 5, 3, 1, 7]

Pictorial Presentation: Sample Solution:

Java Code:

``````import java.util.*;

public class Solution {

public static void main(String[] args) {
int[] nums = {7, 2, 4, 1, 3, 5, 6, 8, 2, 10};
System.out.println("Original array: "+Arrays.toString(nums));
int[] result = partitionArray2(nums);
System.out.println("After partition the said array becomes: " +Arrays.toString(result));
}

public static int[] partitionArray2(int[] nums) {
int i = 0;
int j = nums.length - 1;
while (i < j) {
while (nums[i] % 2 == 0) i++;
while (nums[j] % 2 != 0) j--;
if (i < j) {
int temp = nums[i];
nums[i] = nums[j];
nums[j] = temp;
}
}
return nums;
}
}
```
```

Sample Output:

```Original array: [7, 2, 4, 1, 3, 5, 6, 8, 2, 10]
After partition the said array becomes: [10, 2, 4, 2, 8, 6, 5, 3, 1, 7]
```

Flowchart: Java Code Editor:

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## Java: Tips of the Day

Java: Anagrams

Generates all anagrams of a string.

```public static List<String> anagrams(String input) {
if (input.length() <= 2) {
return input.length() == 2
? Arrays.asList(input, input.substring(1) + input.substring(0, 1))
: Collections.singletonList(input);
}
return IntStream.range(0, input.length())
.mapToObj(i -> new SimpleEntry<>(i, input.substring(i, i + 1)))
.flatMap(entry ->
anagrams(input.substring(0, entry.getKey()) + input.substring(entry.getKey() + 1))
.stream()
.map(s -> entry.getValue() + s))
.collect(Collectors.toList());
}
```