Java: Accept a positive number and repeatedly add all its digits until the result has only one digit
Java Basic: Exercise-183 with Solution
Sum Digits to Single Digit
Write a Java program to accept a positive number and repeatedly add all its digits until the result has only one digit.
Visual Presentation:
Sample Solution:
Java Code:
// Importing necessary Java utilities
import java.util.*;
// Main class Solution
public class Solution {
// Main method
public static void main(String[] args) {
// Creating Scanner object for user input
Scanner in = new Scanner(System.in);
// Prompting user to input a positive integer
System.out.print("Input a positive integer: ");
// Reading the input value provided by the user
int n = in.nextInt();
// Checking if the input is a positive integer
if (n > 0)
// Printing the result of add_digits_until_one method if the input is positive
System.out.println(add_digits_until_one(n));
}
// Method to add digits of a number until the result becomes a single digit
public static int add_digits_until_one(int n) {
// Loop to keep adding digits until the number becomes a single digit
while (n > 9) {
int sum_digits = 0;
// Loop to extract digits and calculate their sum
while (n != 0) {
sum_digits += n % 10; // Adding the last digit to sum
n /= 10; // Removing the last digit
}
n = sum_digits; // Assigning the sum to 'n' for next iteration
}
return n; // Returning the single-digit sum
}
}
Sample Output:
Input a positive integer: 25 7
Flowchart:
Java Code Editor:
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Previous: Write a Java program to check if two binary trees are identical or not. Assume that two binary trees have the same structure and every identical position has the same value.
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