﻿ Java - Test if an array contains an element 10 next to 10

# Java: Test if an array of integers contains an element 10 next to 10 or an element 20 next to 20, but not both

## Java Basic: Exercise-93 with Solution

Write a Java program to test if an array of integers contains an element 10 next to 10 or an element 20 next to 20, but not both.

Sample Solution:

Java Code:

``````import java.util.*;
public class Exercise93 {
public static void main(String[] args) {
// Define an array of integers
int[] nums = {10, 10, 2, 4, 20, 20};

// Initialize counters for even and odd numbers
int ctr_even = 0, ctr_odd = 0;

// Display the original array
System.out.println("Original Array: " + Arrays.toString(nums));

// Initialize boolean variables to check for specific patterns
boolean found1010 = false;
boolean found2020 = false;

// Iterate through the array to find patterns (e.g., 1010 and 2020)
for (int i = 0; i < nums.length - 1; i++) {
if (nums[i] == 10 && nums[i + 1] == 10) {
found1010 = true;
}

if (nums[i] == 20 && nums[i + 1] == 20) {
found2020 = true;
}
}

// Check if the patterns 1010 and 2020 were found and print the result
System.out.printf(String.valueOf(found1010 != found2020));
System.out.printf("\n");
}
}
```
```

Sample Output:

```Original Array: [10, 10, 2, 4, 20, 20]
false
```

Pictorial Presentation:  Flowchart: Java Code Editor:

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