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Java Exercises: Rearrange all the elements of an given array of integers so that all the odd numbers come before all the even numbers

Java Basic: Exercise-94 with Solution

Write a Java program to rearrange all the elements of an given array of integers so that all the odd numbers come before all the even numbers.

Pictorial Presentation:

Java Basic Exercises: Rearrange all the elements of an given array of integers so that all the odd numbers come before all the even numbers

Sample Solution:

Java Code:

import java.util.*; 
import java.io.*; 
 public class Exercise94 {
 public static void main(String[] args)
 {
    int[] array_nums = {1, 7, 8, 5, 7, 13, 0, 2, 4, 9};
	  
	int i = 0;
    System.out.println("Original Array: "+Arrays.toString(array_nums)); 
    while(i < array_nums.length && array_nums[i] % 2 == 0)
        i++;
              
    for(int j = i + 1; j < array_nums.length; j++) {
        if(array_nums[j] % 2 != 0) {
            int temp = array_nums[i];
            array_nums[i] = array_nums[j];
            array_nums[j] = temp;
            i++;
        }
    }                                                    
  
	 System.out.println("New Array: "+Arrays.toString(array_nums)); 
  }
}

Sample Output: 

Original Array: [1, 7, 8, 5, 7, 13, 0, 2, 4, 9]                        
New Array: [7, 5, 7, 13, 9, 1, 0, 2, 4, 8]

Flowchart:

Flowchart: Java exercises: Rearrange all the elements of an given array of integers so that all the odd numbers come before all the even numbers

Java Code Editor:

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Java: Tips of the Day

countOccurrences

Counts the occurrences of a value in an array.

Use Arrays.stream().filter().count() to count total number of values that equals the specified value.

public static long countOccurrences(int[] numbers, int value) {
    return Arrays.stream(numbers)
            .filter(number -> number == value)
            .count();
}

Ref: https://bit.ly/3kCAgLb