JavaScript: Find the maximum integer n
JavaScript Basic: Exercise-145 with Solution
Write a JavaScript program to find the maximum integer n such that 1 + 2 + ... + n <= a given integer.
Sample Solution:
JavaScript Code:
/**
* Function to find the sum of natural numbers up to a given value
* @param {number} val - The value up to which the sum of natural numbers needs to be calculated
* @returns {number} - The number of terms in the sum sequence
*/
function sumn(val) {
var sn = 0; // Initialize the sum of natural numbers
var i = 0; // Initialize the index to 0
// Loop to calculate the sum of natural numbers up to a certain limit
while (sn <= val) {
sn += i++; // Incrementally add the value of 'i' to the sum and increment 'i'
}
return i - 2; // Return the number of terms in the sum sequence (subtracting 2 to account for the extra iteration)
}
// Display the number of terms for different values
console.log(sumn(11)); // Output: 4
console.log(sumn(15)); // Output: 5
Output:
4 5
Live Demo:
See the Pen javascript-basic-exercise-145 by w3resource (@w3resource) on CodePen.
Flowchart:
ES6 Version:
/**
* Function to find the sum of natural numbers up to a given value
* @param {number} val - The value up to which the sum of natural numbers needs to be calculated
* @returns {number} - The number of terms in the sum sequence
*/
const sumn = (val) => {
let sn = 0; // Initialize the sum of natural numbers
let i = 0; // Initialize the index to 0
// Loop to calculate the sum of natural numbers up to a certain limit
while (sn <= val) {
sn += i++; // Incrementally add the value of 'i' to the sum and increment 'i'
}
return i - 2; // Return the number of terms in the sum sequence (subtracting 2 to account for the extra iteration)
};
// Display the number of terms for different values
console.log(sumn(11)); // Output: 4
console.log(sumn(15)); // Output: 5
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