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JavaScript: Break an address of an url and put it's part into an array

JavaScript Basic: Exercise-144 with Solution

Write a JavaScript program to break an address of an url and put it's part into an array.

Note: url structure : ://.org[/] and there may be no part in the address.

Pictorial Presentation:

JavaScript: Break an address of an url and put it's part into an array.

Sample Solution:

HTML Code:

<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <meta name="viewport" content="width=device-width">
  <title>Break an address of an url and put it's part into an array.</title>
</head>
<body>

</body>
</html>

JavaScript Code:

function break_address(url_add) {
    var data = url_add.split("://")
    var protocol = data[0];
    data = data[1].split(".com");
    var domain = data[0];
    data = data[1].split("/");

    if(data[1]){
        return [protocol,domain,data[1]]
    }

    return [protocol,domain]
}

var url_add = "https://www.w3resource.com/javascript-exercises/"
console.log("Original address: "+url_add)
console.log(break_address(url_add))

Sample Output:

Original address: https://www.w3resource.com/javascript-exercises/
["https","www.w3resource","javascript-exercises"]

Flowchart:

Flowchart: JavaScript - Break an address of an url and put it's part into an array

ES6 Version:

function break_address(url_add) {
    let data = url_add.split("://");
    const protocol = data[0];
    data = data[1].split(".com");
    const domain = data[0];
    data = data[1].split("/");

    if(data[1]){
        return [protocol,domain,data[1]]
    }

    return [protocol,domain]
}

var url_add = "https://www.w3resource.com/javascript-exercises/"
console.log(`Original address: ${url_add}`)
console.log(break_address(url_add))

Live Demo:

See the Pen javascript-basic-exercise-144 by w3resource (@w3resource) on CodePen.

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Previous: Write a JavaScript program to sort the strings of a given array of strings in the order of increasing lengths.
Next: Write a JavaScript program to find the maximum integer n such that 1 + 2 + ... + n <= a given integer.

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JavaScript: Tips of the Day

Returns the sum of the powers of all the numbers from start to end (both inclusive)

Example:

const sumPower = (end, power = 2, start = 1) =>
  Array(end + 1 - start)
    .fill(0)
    .map((x, i) => (i + start) ** power)
    .reduce((a, b) => a + b, 0);
console.log(sumPower(10)); // 385
console.log(sumPower(10, 3)); // 3025
console.log(sumPower(10, 3, 5)); // 2925 

Output:

385
3025
2925