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JavaScript: Display the city name if the string begins with "Los" or "New" otherwise return blank

JavaScript Basic: Exercise-66 with Solution

Write a JavaScript program to display the city name if the string begins with "Los" or "New" otherwise return blank.

Visual Presentation:

JavaScript: Display the city name if the string begins with 'Los' or 'New' otherwise return blank

Sample Solution:

JavaScript Code:

// Define a function named city_name with parameter str
function city_name(str) {
  // Check if str has length greater than or equal to 3 and starts with 'Los' or 'New'
  if (str.length >= 3 && ((str.substring(0, 3) == 'Los') || (str.substring(0, 3) == 'New'))) {
    // Return the input str if conditions are met
    return str;
  }

  // Return an empty string if conditions are not met
  return '';
}

// Call the function with sample arguments and log the results to the console
console.log(city_name("New York"));
console.log(city_name("Los Angeles"));
console.log(city_name("London")); 

Output:

New York
Los Angeles

Live Demo:

See the Pen JavaScript - Display the city name if the string begins with "Los" or "New" otherwise return blank - basic-ex-66 by w3resource (@w3resource) on CodePen.


Flowchart:

Flowchart: JavaScript - Display the city name if the string begins with

ES6 Version:

// Define a function named city_name with parameter str
const city_name = (str) => {
    // Use conditional (ternary) operator to check conditions and return the result
    return (str.length >= 3 && (str.substring(0, 3) === 'Los' || str.substring(0, 3) === 'New')) ? str : '';
};

// Call the function with sample arguments and log the results to the console
console.log(city_name("New York"));
console.log(city_name("Los Angeles"));
console.log(city_name("London"));

Improve this sample solution and post your code through Disqus.

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