# JavaScript: Distinct ways to climb the staircase

## JavaScript Math: Exercise-104 with Solution

A staircase consists of N steps, and you are given the choice of climbing one step at a time or two steps at a time.

Write a JavaScript program to find distinct ways to climb the staircase.

Example:

Number of stairs = 2

There are 2 ways to climb the stairs: (1,1) and (2)

Number of stairs = 3

There are 3 ways to climb the stairs: (1,1,1), (2,1) and (1,2)

**Visualisation:**

**Test Data:**

(2) -> 2

(3) -> 3

**Sample Solution:**

**HTML Code:**

```
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript program to Distinct ways to climb the staircase</title>
</head>
<body>
</body>
</html>
```

**Solution-1**

**JavaScript Code:**

```
function test(n) {
var x = 0,
y = 1;
while(n-->0){
y = x + y;
x = y - x;
}
return b;
}
n = 2
console.log("Number of stairs = " +n)
console.log("Number of ways to climb the said number of stairs: "+test(n));
n = 3
console.log("Number of stairs = " +n)
console.log("Number of ways to climb the said number of stairs: "+test(n));
```

Sample Output:

Number of stairs = 2

**Flowchart: **

**Live Demo: **

See the Pen javascript-math-exercise-104 by w3resource (@w3resource) on CodePen.

**Solution-2**

**JavaScript Code:**

```
function test(n) {
nums=[];
nums[1]=1;
nums[2]=2;
for(i=3;i<=n;i++){
nums[i]=nums[i-1]+nums[i-2];
}
return nums[n];
}
n = 2
console.log("Number of stairs = " +n)
console.log("Number of ways to climb the said number of stairs: "+test(n));
n = 3
console.log("Number of stairs = " +n)
console.log("Number of ways to climb the said number of stairs: "+test(n));
```

Sample Output:

Number of stairs = 2 Number of ways to climb the said number of stairs: 2 Number of stairs = 3 Number of ways to climb the said number of stairs: 3

**Flowchart: **

**Live Demo: **

See the Pen javascript-math-exercise-104-1 by w3resource (@w3resource) on CodePen.

**Improve this sample solution and post your code through Disqus**

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