Python: Show the individual process IDs involved
Python Basic - 1: Exercise-118 with Solution
In multiprocessing, processes are spawned by creating a Process object.
Write a Python program to show the individual process IDs (parent process, process ID etc.) involved.
Sample Solution:
Python Code:
from multiprocessing import Process
import os
def info(title):
print(title)
print('module name:', __name__)
print('parent process:', os.getppid())
print('process id:', os.getpid())
def f(name):
info('function f')
print('hello', name)
if __name__ == '__main__':
info('Main line')
p = Process(target=f, args=('bob',))
p.start()
p.join()
Sample Output:
Main line module name: __main__ parent process: 23967 process id: 27986 function f module name: __main__ parent process: 27986 process id: 27987 hello bob
Flowchart:

Python Code Editor:
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Python: Tips of the Day
Returns the symmetric difference between two lists, after applying the provided function to each list element of both:
Example:
def tips_symmetric_difference_by(p, q, fn): _p, _q = set(map(fn, p)), set(map(fn, q)) return [item for item in p if fn(item) not in _q] + [item for item in q if fn(item) not in _p] from math import floor print(tips_symmetric_difference_by([4.2, 2.4], [4.6, 6.8],floor))
Output:
[2.4, 6.8]
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