# Python: Get all possible two digit letter combinations from a digit string

## Python Basic - 1: Exercise-13 with Solution

Write a Python program to get all possible two-digit letter combinations from a 1-9 digit string.

string_maps = {

"1": "abc",

"2": "def",

"3": "ghi",

"4": "jkl",

"5": "mno",

"6": "pqrs",

"7": "tuv",

"8": "wxy",

"9": "z"

}

**Pictorial Presentation:**

**Sample Solution**:

**Python Code:**

```
def letter_combinations(digits):
if digits == "":
return []
string_maps = {
"1": "abc",
"2": "def",
"3": "ghi",
"4": "jkl",
"5": "mno",
"6": "pqrs",
"7": "tuv",
"8": "wxy",
"9": "z"
}
result = [""]
for num in digits:
temp = []
for an in result:
for char in string_maps[num]:
temp.append(an + char)
result = temp
return result
digit_string = "47"
print(letter_combinations(digit_string))
digit_string = "29"
print(letter_combinations(digit_string))
```

Sample Output:

['jt', 'ju', 'jv', 'kt', 'ku', 'kv', 'lt', 'lu', 'lv'] ['dz', 'ez', 'fz']

**Flowchart:**

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**Python Code Editor :**

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**Previous:** Write a Python program to create all possible permutations from a given collection of distinct numbers.

**Next:** Write a Python program to add two positive integers without using the '+' operator.

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## Python: Tips of the Day

**Returns the symmetric difference between two iterables, without filtering out duplicate values:**

Example:

def tips_symmetric_difference(p, q): _p, _q = set(p), set(q) return [item for item in p if item not in _q] + [item for item in q if item not in _p] print(tips_symmetric_difference([2, 4, 6], [2, 4, 8]))

Output:

[6, 8]

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