Python: nth Hamming number
Python Itertools: Exercise-26 with Solution
Write a Python program to find the nth Hamming number. Use the itertools module.
Hamming numbers are numbers of the form
H = 2i x 3j x 5k Where i, j, k ≥ 0
The sequence of Hamming numbers 1, 2, 3, 4, 5, 6, 8, 9, 10, 12, 15, 16, 18, 20, 24, 25, 27. . . consists of all numbers of the form 2i.3j.5k where i, j and k are non-negative integers.
import itertools from heapq import merge def nth_hamming_number(n): def num_recur(): last = 1 yield last x, y, z = itertools.tee(num_recur(), 3) for n in merge((2 * i for i in x), (3 * i for i in y), (5 * i for i in z)): if n != last: yield n last = n result = itertools.islice(num_recur(), n) return list(result)[-1] print(nth_hamming_number(8)) print(nth_hamming_number(14)) print(nth_hamming_number(17))
9 20 27
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