# Python: Find the first two elements of a given list whose sum is equal to a given value

## Python Itertools: Exercise-25 with Solution

Write a Python program to find the first two elements of a given list whose sum is equal to a given value. Use the itertools module to solve the problem.

**Sample Solution:**

**Python Code:**

```
import itertools as it
def sum_pairs_list(nums, n):
for num2, num1 in list(it.combinations(nums[::-1], 2))[::-1]:
if num2 + num1 == n:
return [num1, num2]
nums = [1,2,3,4,5,6,7]
n = 10
print("Original list:",nums,": Given value:",n)
print("Sum of pair equal to ",n,"=",sum_pairs_list(nums,n))
nums = [1,2,-3,-4,-5,6,-7]
n = -6
print("Original list:",nums,": Given value:",n)
print("Sum of pair equal to ",n,"=",sum_pairs_list(nums,n))
```

Sample Output:

Original list: [1, 2, 3, 4, 5, 6, 7] : Given value: 10 Sum of pair equal to 10 = [4, 6] Original list: [1, 2, -3, -4, -5, 6, -7] : Given value: -6 Sum of pair equal to -6 = [1, -7]

**Python Code Editor:**

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