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Python: Pack consecutive duplicates of a given list elements into sublists

Python List: Exercise - 74 with Solution

Write a Python program to pack consecutive duplicates of a given list elements into sublists.

Sample Solution:

Python Code:

from itertools import groupby
def pack_consecutive_duplicates(l_nums):
    return [list(group) for key, group in groupby(l_nums)]
n_list = [0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4 ]
print("Original list:") 
print(n_list)
print("\nAfter packing consecutive duplicates of the said list elements into sublists:")
print(pack_consecutive_duplicates(n_list)) 


Sample Output:

Original list:
[0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]

After packing consecutive duplicates of the said list elements into sublists:
[[0, 0], [1], [2], [3], [4, 4], [5], [6, 6, 6], [7], [8], [9], [4, 4]]

Flowchart:

Flowchart: Pack consecutive duplicates of a given list elements into sublists.

Visualize Python code execution:

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Python Code Editor:

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Python: Tips of the Day

Floor Division:

When we speak of division we normally mean (/) float division operator, this will give a precise result in float format with decimals.

For a rounded integer result there is (//) floor division operator in Python. Floor division will only give integer results that are round numbers.

print(1000 // 300)
print(1000 / 300)

Output:

3
3.3333333333333335