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Python: Remove consecutive duplicates of a given list

Python List: Exercise - 73 with Solution

Write a Python program to remove consecutive (following each other continuously) duplicates (elements) from a given list.

Sample Solution:

Python Code:

from itertools import groupby
def compress(l_nums):
    return [key for key, group in groupby(l_nums)] 
n_list = [0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4 ]
print("Original list:") 
print(n_list)
print("\nAfter removing consecutive duplicates:")
print(compress(n_list))

Sample Output: 

Original list:
[0, 0, 1, 2, 3, 4, 4, 5, 6, 6, 6, 7, 8, 9, 4, 4]

After removing consecutive duplicates:
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 4]

Flowchart:

Flowchart: Remove consecutive duplicates of a given list.

Visualize Python code execution:

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Python Code Editor:

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Previous: Write a Python program to flatten a given nested list structure.
Next: Write a Python program to pack consecutive duplicates of a given list elements into sublists.

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Python: Tips of the Day

Creates a list of elements, grouped based on the position in the original lists:

Example:

def tips_zip(*args, fill_value=None):
  	max_length = max([len(lst) for lst in args])
 	 result = []
  	for i in range(max_length):
   	 result.append([
      args[k][i] if i < len(args[k]) else fillvalue for k in range(len(args))
   	 ])
 	 return result
print(tips_zip(['a', 'b'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False]))
print(tips_zip(['a'], [1, 2], [True, False], fill_value = '1'))

Output:

[['a', 1, True], ['b', 2, False]]
[['a', 1, True], [None, 2, False]]
[['a', 1, True], ['1', 2, False]]