Python Math: Find the smallest multiple of the first n numbers
Python Math: Exercise-10 with Solution
Write a Python program to find the smallest multiple of the first n numbers. Also, display the factors.
def smallest_multiple(n): if (n<=2): return n i = n * 2 factors = [number for number in range(n, 1, -1) if number * 2 > n] print(factors) while True: for a in factors: if i % a != 0: i += n break if (a == factors[-1] and i % a == 0): return i print(smallest_multiple(13)) print(smallest_multiple(11)) print(smallest_multiple(2)) print(smallest_multiple(1))
[13, 12, 11, 10, 9, 8, 7] 360360 [11, 10, 9, 8, 7, 6] 27720 2 1
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Next: Write a Python program to calculate the difference between the squared sum of first n natural numbers and the sum of squared first n natural numbers.(default value of number=2).
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