w3resource

Python Math: Calculate the difference between the squared sum and the sum of squared of first n natural numbers

Python Math: Exercise-11 with Solution

Write a Python program to calculate the difference between the squared sum of first n natural numbers and the sum of squared first n natural numbers.(default value of number=2).

Sample Solution:-

Python Code:

def sum_difference(n=2):
    sum_of_squares = 0
    square_of_sum = 0
    for num in range(1, n+1):
        sum_of_squares += num * num
        square_of_sum += num

    square_of_sum = square_of_sum ** 2

    return square_of_sum - sum_of_squares


print(sum_difference(12))

Sample Output:

5434

Pictorial Presentation:

Python Math: Calculate difference between squared sum and sum of squared of first n natural numbers

Flowchart:

Flowchart: Calculate difference between squared sum and sum of squared of first n natural numbers

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:

Python Code Editor:

Have another way to solve this solution? Contribute your code (and comments) through Disqus.

Previous: Write a Python program to find the smallest multiple of the first n numbers. Also, display the factors.
Next: Write a Python program to calculate the sum of all digits of the base to the specified power.

What is the difficulty level of this exercise?

Test your Python skills with w3resource's quiz



Python: Tips of the Day

Python: Get the Key Whose Value Is Maximal in a Dictionary

>>> model_scores = {'model_a': 100, 'model_z': 198, 'model_t': 150}
>>> # workaround
>>> keys, values = list(model_scores.keys()), list(model_scores.values())
>>> keys[values.index(max(values))]
'model_z'
>>> # one-line
>>> max(model_scores, key=model_scores.get)
'model_z'