# C Exercises: Find the number of trailing zeroes in a given factorial

## C Programming Mathematics: Exercise-10 with Solution

Write a C program to find the number of trailing zeroes in a given factorial.

Example 1:

Input: 4

Output: 0

Explanation: 4! = 24, no trailing zero.

Example 2:

Input: 6

Output: 1

Explanation: 6! = 720, one trailing zero.

Example:

Input:

n = 4

n = 5

Output:

Number of trailing zeroes of factorial 4 is 0

Number of trailing zeroes of factorial 5 is 1

**Visual Presentation:**

**Sample Solution:**

**C Code:**

```
#include <stdio.h>
// Function to count the number of trailing zeroes in the factorial of a number
static int trailing_Zeroes(int n) {
int number = 0;
// Loop to calculate the number of trailing zeroes
while (n > 0) {
number += n / 5; // Count how many multiples of 5 are present in the factorial
n /= 5; // Divide the number by 5 to check for the next multiple of 5
}
return number; // Return the count of trailing zeroes
}
// Main function to test the trailing_Zeroes function with different values
int main(void) {
int n = 4;
printf("\nNumber of trailing zeroes of factorial %d is %d ", n, trailing_Zeroes(n)); // Display the number of trailing zeroes for n
n = 5;
printf("\nNumber of trailing zeroes of factorial %d is %d ", n, trailing_Zeroes(n)); // Display the number of trailing zeroes for n
return 0;
}
```

Sample Output:

Number of trailing zeroes of factorial 4 is 0 Number of trailing zeroes of factorial 5 is 1

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