# JavaScript: Check if the given number falls within the given range

## JavaScript fundamental (ES6 Syntax): Exercise-217 with Solution

Write a JavaScript program to check if the given number falls within the given range.

• Use arithmetic comparison to check if the given number is in the specified range.
• If the second argument, end, is not specified, the range is considered to be from 0 to start.

Sample Solution:

JavaScript Code:

``````// Define a function 'inRange' that checks if a number 'n' is within a specified range defined by 'start' and 'end' values
const inRange = (n, start, end = null) => {
// If 'end' is provided and 'start' is greater than 'end', swap their values
if (end && start > end) end = [start, (start = end)][0];
// If 'end' is not provided, check if 'n' is greater than or equal to 0 and less than 'start'
return end == null ? n >= 0 && n < start : n >= start && n < end;
};

// Test the 'inRange' function with sample inputs
console.log(inRange(3, 2, 5));
console.log(inRange(3, 4));
console.log(inRange(2, 3, 5));
console.log(inRange(3, 2));
```
```

Output:

```true
true
false
false
```

Flowchart:

Live Demo:

See the Pen javascript-basic-exercise-217-1 by w3resource (@w3resource) on CodePen.

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