Python: Check if the elements of the first list are contained in the second one regardless of order
Python List: Exercise - 270 with Solution
Write a Python program to check if the elements of the first list are contained in the second one regardless of order.
- Use count() to check if any value in a has more occurrences than it has in b.
- Return False if any such value is found, True otherwise.
def is_contained_in(l1, l2): for x in set(l1): if l1.count(x) > l2.count(x): return False return True print(is_contained_in([1, 2], [2, 4, 1])) print(is_contained_in(, [2, 4, 1])) print(is_contained_in([1, 1], [4, 2, 1])) print(is_contained_in([1, 1], [3, 2, 4, 1, 5, 1]))
True True False True
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