Python: Check if the elements of the first list are contained in the second one regardless of order

Python List: Exercise - 270 with Solution

Write a Python program to check if the elements of the first list are contained in the second one regardless of order.

• Use count() to check if any value in a has more occurrences than it has in b.
• Return False if any such value is found, True otherwise.

Sample Solution:

Python Code:

def is_contained_in(l1, l2):
  for x in set(l1):
    if l1.count(x) > l2.count(x):
      return False
  return True
print(is_contained_in([1, 2], [2, 4, 1]))
print(is_contained_in([1], [2, 4, 1]))
print(is_contained_in([1, 1], [4, 2, 1]))
print(is_contained_in([1, 1], [3, 2, 4, 1, 5, 1]))

Sample Output:

True
True
False
True

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