Python: Get every nth element in a given list
Python List: Exercise - 269 with Solution
Write a Python program to get every nth element in a given list.
Use slice notation to create a new list that contains every nth element of the given list
Sample Solution:
Python Code:
def every_nth(nums, nth):
return nums[nth - 1::nth]
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 1))
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 2))
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 5))
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 6))
Sample Output:
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] [2, 4, 6, 8, 10] [5, 10] [6]
Flowchart:

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Python Code Editor:
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Next: Write a Python program to check if the elements of the first list are contained in the second one regardless of order.
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Python: Tips of the Day
Decapitalizes the first letter of a string:
Example:
def tips_decapitalize(s, upper_rest=False): return s[:1].lower() + (s[1:].upper() if upper_rest else s[1:]) print(tips_decapitalize('PythonTips')) print(tips_decapitalize('PythonTips', True))
Output:
pythonTips pYTHONTIPS
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