# Python: Get every nth element in a given list

## Python List: Exercise - 269 with Solution

Write a Python program to get every nth element in a given list.

Use slice notation to create a new list that contains every nth element of the given list

**Sample Solution:**

**Python Code:**

```
# Define a function named 'every_nth' that returns every nth element from a list.
# It takes two parameters: 'nums' (the list) and 'nth' (the interval for selecting elements).
def every_nth(nums, nth):
# Use list slicing to return elements starting from the (nth-1) index, with a step of 'nth'.
return nums[nth - 1::nth]
# Create a sample list of integers from 1 to 10.
nums = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
# Print the original list elements.
print(every_nth(nums, 1)) # Select every 1st element (no change).
print(every_nth(nums, 2)) # Select every 2nd element.
print(every_nth(nums, 5)) # Select every 5th element.
print(every_nth(nums, 6)) # Select every 6th element.
```

Sample Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10] [2, 4, 6, 8, 10] [5, 10] [6]

**Flowchart:**

**Python Code Editor:**

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**Next:** Write a Python program to check if the elements of the first list are contained in the second one regardless of order.

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