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Python: Get every nth element in a given list

Python List: Exercise - 269 with Solution

Write a Python program to get every nth element in a given list.

Use slice notation to create a new list that contains every nth element of the given list

Sample Solution:

Python Code:

def every_nth(nums, nth):
  return nums[nth - 1::nth]
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 1))
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 2))
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 5))
print(every_nth([1, 2, 3, 4, 5, 6, 7, 8, 9, 10], 6))

Sample Output:

[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
[2, 4, 6, 8, 10]
[5, 10]
[6]

Flowchart:

Flowchart: Get every nth element in a given list.

Visualize Python code execution:

The following tool visualize what the computer is doing step-by-step as it executes the said program:


Python Code Editor:

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Next: Write a Python program to check if the elements of the first list are contained in the second one regardless of order.

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Python: Tips of the Day

Decapitalizes the first letter of a string:

Example:

def tips_decapitalize(s, upper_rest=False):
  return s[:1].lower() + (s[1:].upper() if upper_rest else s[1:])
print(tips_decapitalize('PythonTips'))
print(tips_decapitalize('PythonTips', True)) 

Output:

pythonTips
pYTHONTIPS

 





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