JavaScript: Sum the multiples of 3 and 5 under 1000

JavaScript Conditional Statement and loops: Exercise-12 with Solution

Sum of Multiples of 3 and 5 under 1000

Write a JavaScript program to sum 3 and 5 multiples under 1000.

Sample Solution

JavaScript Code:

// Variable to store the sum of numbers divisible by 3 or 5
var sum = 0;

// Loop through numbers from 0 to 999
for (var x = 0; x < 1000; x++) {
    // Check if the current number is divisible by 3 or 5
    if (x % 3 === 0 || x % 5 === 0) {
        // Add the current number to the sum
        sum += x;
    }
}

// Output the final sum
console.log(sum); 

Output:

233168

Flowchart:

Live Demo:

See the Pen javascript-conditional-statements-and-loops-exercise-12 by w3resource (@w3resource) on CodePen.

For more Practice: Solve these Related Problems:

• Write a JavaScript function that calculates the sum of all multiples of 3 and 5 below 1000 using a loop with conditional checks.
• Write a JavaScript function that computes the sum of multiples of 3 and 5 under 1000 using the arithmetic series formula.
• Write a JavaScript function that uses recursion to sum all multiples of 3 and 5 below 1000.
• Write a JavaScript function that iterates through numbers below 1000 and sums those that are multiples of 3 or 5 while optimizing for performance.

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• JavaScript conditional statements and loops Exercises Home ↩
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