C Exercises: Rearrange an array in such an order that– smallest, largest, 2nd smallest, 2nd largest and on

C Array: Exercise-102 with Solution

Write a program in C to rearrange an array in such an order that– small, large, second smallest, second largest, etc.

Sample Solution:

C Code:

#include<stdio.h> 
void sort(int arr1[], int n) 
{ 
   int i, j,temp; 
   for (i = 0; i < n-1; i++)
	{   
       for (j = 0; j < n-i-1; j++)
       {
           if (arr1[j] > arr1[j+1])
           {
               temp = arr1[j]; 
               arr1[j] = arr1[j+1]; 
               arr1[j+1] = temp;
           }
       }
	}   
    return ;
} 
  
void rearrangeArray(int arr1[], int n) 
{   
    sort(arr1, n); 
    int tempArr[n];  
    int ArrIndex = 0;
    for (int i = 0, j = n-1; i <= n / 2 || j > n / 2; i++, j--) 
	{ 
        tempArr[ArrIndex] = arr1[i]; 
        ArrIndex++; 
        tempArr[ArrIndex] = arr1[j]; 
        ArrIndex++; 
    } 
    for (int i = 0; i < n; i++) 
        {arr1[i] = tempArr[i];}
} 
  
int main() 
{ 
    int arr1[] = { 5, 8, 1, 4, 2, 9, 3, 7, 6 };    
    int n = sizeof(arr1) / sizeof(arr1[0]); 
	    int i = 0; 
   //------------- print original array ------------------	
	printf("The given array is:  \n");
	for(i = 0; i < n; i++)
		{
			printf("%d  ", arr1[i]);
		}
	printf("\n");
//-----------------------------------------------------------  
	printf("The new array is:  \n");
    rearrangeArray(arr1, n); 
    for (int i = 0; i < n; i++) 
        printf("%d ",arr1[i]); 
    return 0; 
}

Sample Output:

The given array is:  
5  8  1  4  2  9  3  7  6  
The new array is:  
1 9 2 8 3 7 4 6 5  

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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