C Exercises: Find the ceiling in a sorted array
C Array: Exercise-40 with Solution
Write a program in C to find the ceiling in a sorted array.
N.B.: Given a sorted array in ascending order and a value x, the ceiling of x is the smallest element in array greater than or equal to x,
and the floor is the greatest element smaller than or equal to x.
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
int findCeiling(int arr1[], int low, int high, int x)
{
int i;
if (x <= arr1[low])
return low;
for (i = low; i < high; i++)
{
if (arr1[i] == x)
return i;
if (arr1[i] < x && arr1[i + 1] >= x)
return i + 1;
}
return -1;
}
int main()
{
int arr1[] = {1, 3, 4, 7, 8, 9, 9, 10};
int ctr = sizeof(arr1)/sizeof(arr1[0]);
int x = 5,i;
//------------- print original array ------------------
printf("The given array is : ");
for(i = 0; i < ctr; i++)
{
printf("%d ", arr1[i]);
}
printf("\n");
//----------------------------------------------------
int index = findCeiling(arr1, 0, ctr-1, x);
if (index == -1)
printf("No ceiling for the number %d exists in array. ", x);
else
printf("The ceiling of %d is: %d", x, arr1[index]);
getchar();
return 0;
}
Sample Output:
The given array is : 1 3 4 7 8 9 9 10 The ceiling of 5 is: 7
Flowchart:

C Programming Code Editor:
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Previous: Write a program in C to rotate an array by N positions.
Next: Write a program in C to find the Floor and Ceil of the number 0 to 10 from a sroted array.
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