C Exercises: Find the number of times occurs a given number in an array

C Array: Exercise-53 with Solution

Write a program in C to find the number of times a given number appears in an array.

Pictorial Presentation:

Sample Solution:

C Code:

#include <stdio.h>
int BinSearch(int arr1[], int n, int x, int searchFirst)
{
    int low = 0, high = n - 1;
    int result = -1;
    while (low <= high)
    {
        int mid = (low + high)/2;
        if (x == arr1[mid])
        {
            result = mid;
            if (searchFirst)
                high = mid - 1;
            else
                low = mid + 1;
        }
        else if (x < arr1[mid])
            high = mid - 1;
        else
            low = mid + 1;
    }
    return result;
}

int main(void)
{
    int arr1[] = {2, 3, 4, 4, 4, 4, 5, 5, 5, 6, 7, 7};
    int srch_num = 4;
    int n = sizeof(arr1)/sizeof(arr1[0]);
	int i;
 //------------- print original array ------------------	
	printf("The given array is :  ");
	for(i = 0; i < n; i++)
	{
	printf("%d  ", arr1[i]);
    } 
	printf("\n");
//------------------------------------------------------ 	
    int first = BinSearch(arr1, n, srch_num, 1); 
    int last = BinSearch(arr1, n, srch_num, 0);  
    int ctr = last - first + 1;
    if (first != -1)
        printf("The number of times the number %d occurs in the given array is:  %d", srch_num, ctr);
    else
        printf("No such element found in the array.");
    return 0;
}

Sample Output:

The given array is :  2  3  4  4  4  4  5  5  5  6  7  7  
The number of times the number 4 occurs in the given array is:  4

Flowchart:

C Programming Code Editor:

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