﻿ C Program: Minimum element in a sorted and rotated array

# C Exercises: Find minimum element in a sorted and rotated array

## C Array: Exercise-57 with Solution

Write a program in C to find the minimum element in a sorted and rotated array.

Visual Presentation:

Sample Solution:

C Code:

``````#include <stdio.h>

// Function to find the minimum element in a rotated sorted array
int findMin(int arr1[], int start, int end) {
// If the start index and end index are the same, return the element at that index
if (start == end) {
return arr1[start];
}

// Find the middle index
int mid = (start + end) / 2;

// If the element at the start index is greater than the element at the middle index,
// the minimum element lies in the left half, so search in that half
if (arr1[start] > arr1[mid]) {
return findMin(arr1, start, mid);
} else if (arr1[mid] > arr1[end]) {
// If the element at the middle index is greater than the element at the end index,
// the minimum element lies in the right half, so search in that half
return findMin(arr1, mid + 1, end);
} else {
// If none of the conditions are met, the array is not rotated or only partially rotated,
// so the minimum element is at the start index
return arr1[start];
}
}

int main() {
int arr1[] = {3, 4, 5, 6, 7, 9, 2};
int n = sizeof(arr1) / sizeof(arr1[0]);
int i;

//------------- print original array ------------------
printf("The given array is: ");
for (i = 0; i < n; i++) {
printf("%d ", arr1[i]);
}
printf("\n");
//------------------------------------------------------

// Find and print the minimum element in the rotated sorted array
int min = findMin(arr1, 0, n - 1);
printf("The minimum element in the above array is: %d\n", min);

return 0;
}
```
```

Sample Output:

```The given array is :  3  4  5  6  7  9  2
The minimum element in the above array is: 2
```

Flowchart:

C Programming Code Editor:

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