C Exercises: Find minimum element in a sorted and rotated array
C Array: Exercise-57 with Solution
Write a program in C to find the minimum element in a sorted and rotated array.
Pictorial Presentation:

Sample Solution:
C Code:
#include <stdio.h>
int findMin(int arr1[],int start,int end)
{
if(start == end)
{
return arr1[start];
}
int mid = (start+end)/2;
if(arr1[start] > arr1[mid])
{
return findMin(arr1,start,mid);
}
else
if(arr1[mid] > arr1[end])
{
return findMin(arr1,mid+1,end);
}
else
{
return arr1[start];
}
}
int main()
{
int arr1[] = { 3,4,5,6,7,9,2 };
int n = sizeof(arr1)/sizeof(arr1[0]);
int i;
//------------- print original array ------------------
printf("The given array is : ");
for(i = 0; i < n; i++)
{
printf("%d ", arr1[i]);
}
printf("\n");
//------------------------------------------------------
int min = findMin(arr1,0,n-1);
printf("The minimum element in the above array is: %d ",min);
return 0;
}
Sample Output:
The given array is : 3 4 5 6 7 9 2 The minimum element in the above array is: 2
Flowchart:

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Next: Write a program in C to move all zeroes to the end of a given array.
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C Programming: Tips of the Day
C Programming - What is the argument for printf that formats a long?
Put an l (lowercased letter L) directly before the specifier.
unsigned long n; long m; printf("%lu %ld", n, m);
Ref : https://bit.ly/3dIwfkP
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