# C Exercises: Compute the sum of the two given integer values. If the two values are the same, then return triple their sum

## C-programming basic algorithm: Exercise-1 with Solution

Write a C program to compute the sum of the two input values. If the two values are the same, then return triple their sum.

**C Code:**

```
#include <stdio.h> // Include standard input/output library
int test(int x, int y); // Declare the function 'test' with two integer parameters
int main(void)
{
// Call the function 'test' with arguments 1 and 2 and print the result
printf("%d", test(1, 2));
// Print a newline for formatting
printf("\n");
// Call the function 'test' with arguments 2 and 2 and print the result
printf("%d", test(2, 2));
}
// Function definition for 'test'
int test(int x, int y)
{
// Conditional expression: If x is equal to y, return (x + y) multiplied by 3, otherwise return x + y
return x == y ? (x + y) * 3 : x + y;
}
```

Sample Output:

3 12

**Explanation:**

int test(int x, int y) { return x == y ? (x + y) * 3 : x + y; }

The above function takes in two integer parameters, x and y. It uses the ternary operator to check if x is equal to y. If x is equal to y, it returns the result of (x + y)*3. Otherwise, it returns the result of x + y.

**Time complexity and space complexity:**

Time complexity: The time complexity of the function is O(1) as the function involves a single conditional operation and two arithmetic operations that take constant time.

Space complexity: The space complexity of the function is O(1) as the function only uses a fixed amount of space to store the variables and the return value.

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**Flowchart:**

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