﻿ C Program: Convert a given integer to years, months and days - w3resource

# C Exercises: Convert a given integer to years, months and days

## C Basic Declarations and Expressions: Exercise-18 with Solution

Write a C program to convert a given integer (in days) to years, months and days, assumes that all months have 30 days and all years have 365 days.

C Code:

``````#include <stdio.h>
int main() {
int ndays, y, m, d;

printf("Input no. of days: ");

scanf("%d", &ndays);

y = (int) ndays/365;

ndays = ndays-(365*y);

m = (int)ndays/30;

d = (int)ndays-(m*30);

printf(" %d Year(s) \n %d Month(s) \n %d Day(s)", y, m, d);
return 0;
}
``````

Sample Output:

```Input no. of days: 2535
6 Year(s)
11 Month(s)
15 Day(s)
```

Flowchart:

C Programming Code Editor:

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## C Programming: Tips of the Day

What's the point of const pointers?

const is a tool which you should use in pursuit of a very important C++ concept:

Find bugs at compile-time, rather than run-time, by getting the compiler to enforce what you mean.

Even though it does not change the functionality, adding const generates a compiler error when you're doing things you didn't mean to do. Imagine the following typo:

```void foo(int* ptr)
{
ptr = 0;// oops, I meant *ptr = 0
}
```

If you use int* const, this would generate a compiler error because you're changing the value to ptr. Adding restrictions via syntax is a good thing in general. Just don't take it too far -- the example you gave is a case where most people don't bother using const.

Ref : https://bit.ly/33Cdn3Q