C Exercises: Convert a given integer to years, months and days
C Basic Declarations and Expressions: Exercise-18 with Solution
Write a C program to convert a given integer (in days) to years, months and days, assumes that all months have 30 days and all years have 365 days.

C Code:
#include <stdio.h>
int main() {
int ndays, y, m, d;
printf("Input no. of days: ");
scanf("%d", &ndays);
y = (int) ndays/365;
ndays = ndays-(365*y);
m = (int)ndays/30;
d = (int)ndays-(m*30);
printf(" %d Year(s) \n %d Month(s) \n %d Day(s)", y, m, d);
return 0;
}
Sample Output:
Input no. of days: 2535 6 Year(s) 11 Month(s) 15 Day(s)
Flowchart:

C Programming Code Editor:
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Previous: Write a C program to convert a given integer (in seconds) to hours, minutes and seconds.
Next: Write a C program that accepts 4 integers p, q, r, s from the user where q, r and s are positive and p is even. If q is greater than r and s is greater than p and if the sum of r and s is greater than the sum of p and q print "Correct values", otherwise print "Wrong values".
What is the difficulty level of this exercise?
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C Programming: Tips of the Day
What's the point of const pointers?
const is a tool which you should use in pursuit of a very important C++ concept:
Find bugs at compile-time, rather than run-time, by getting the compiler to enforce what you mean.
Even though it does not change the functionality, adding const generates a compiler error when you're doing things you didn't mean to do. Imagine the following typo:
void foo(int* ptr) { ptr = 0;// oops, I meant *ptr = 0 }
If you use int* const, this would generate a compiler error because you're changing the value to ptr. Adding restrictions via syntax is a good thing in general. Just don't take it too far -- the example you gave is a case where most people don't bother using const.
Ref : https://bit.ly/33Cdn3Q
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