C Exercises: Find all numbers which are dividing by 7 and the remainder is equal to 2 or 3 between two given integer numbers

C Basic Declarations and Expressions: Exercise-40 with Solution

Find integers divisible by 7 with a remainder of 2 or 3

Write a C program that finds all integer numbers that divide by 7 and have a remainder of 2 or 3 between two given integers.

Sample Solution:

C Code:

#include <stdio.h>
int main() {
    int x, y, temp, i, sum=0;

    // Prompt for user input
    printf("\nInput the first integer: ");
    scanf("%d", &x);
    printf("\nInput the second integer: ");
    scanf("%d", &y);

    // Swap values if x is greater than y
    if(x > y) {
        temp = y;
        y = x;
        x = temp;
    }

    // Iterate through numbers between x and y (exclusive)
    for(i = x+1; i < y; i++) {
        // Check if the number modulo 7 is 2 or 3
        if((i%7) == 2 || (i%7) == 3) {
            printf("%d\n", i);
        }
    }

    return 0;
}

Sample Output:

Input the first integer: 25                                            
                                                                       
Input the second integer: 45                                           
30                                                                     
31                                                                     
37                                                                     
38                                                                     
44

Flowchart:

C programming Code Editor:

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